This is the answer to the age algebra word problem that asked, "Bob is one third the age of his father. In 12 years he will be half the age of his father. How old is each now?"
Ok Bob being 1/3 the age of his father is the same thing as saying the father is 3 times as old as him. It makes it easier to work with. So let Bob be x and his father be 3x. And in 12 years bob will be half as old as his father. So we have..
x + 12 = (3x + 12) / 2
2x + 24 = 3x + 12
x = 12
So Bob is 12 years old and his father is 3(12) or 36 years old now. In 12 years Bob will be 12 + 12 or 24 years old and his father will be 36 + 12 or 48 years old which means Bob will be half as old so it checks out.
Tuesday, December 14, 2010
Age Problem 6 Solution
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wow!!!!!
ReplyDelete48 is the age of the father right?
ReplyDeletethat is correct..
ReplyDeletesick la
ReplyDeletejust think of it and maybe you will get your answer without a solving materials
ReplyDelete36 ang age ng father!!!!
ReplyDeleteshunga
why the answer is not negative?
ReplyDeletein the reason that you move 24 at the left side?
murag conflict lage 2 ang translation noh!!!!!!!! kung lisulisoun nimo ang imong utok, you wil com up with that solution, pero maka sakit man ug ulo, lantaw nalng sa solution........ he, he, nag rhym lage...
ReplyDeletetaga-asa ka oi
Deletetaga-asa ka oi
DeleteLET X =age of the father
ReplyDelete1 1
- X + 12 = - X
3 2
1 1
-X - -X = -12
3 2
-1
-X = -12
6
X = (-12)(-6)
X = 72 AGE OF THE FATHER
AGE OF BOB = 1
- (72)
2
AGE OF BOB = 36
easy!!!!!
ReplyDeletehow could this be !! explain this to me ! if u transpose that terms into their similar terms !!! the value will be gone !
ReplyDeleteoi...wag mo nman laitin..
ReplyDeletei still don't get it! damn! i;m so slow with this :(
ReplyDeleteA man and his wife have ages that total 98. He is twice as old as she was when he was as old as she is now. Find current ages.
ReplyDeleteb=1/3(f) --->present; in 12yrs: b=1/2(f)+12 -->eq1
ReplyDeletef=f -->present; in 12 yrs:f=f+12
but also in 12 yrs: b=1/3(f+12)--->eq2
1/2(f)+12=1/3(f+12)
1/2(f)-1/3(f)=6-12
-1/6(f)=-6
f=36 --->age of Father
if b=1/3(f)
b=1/3(36)
b=12 --->age of Bob
let m for the man and w for the wife, for the problem:
ReplyDeleteA man and his wife have ages that total 98. He is twice as old as she was when he was as old as she is now. Find current ages.
total ages of m+w=98
and m=2w; while w=w
let the equation be like this to solve the problem:
2w+w=98-2
3w=96
w=32; the age of wife now
m=2(32)
m=64; the age of man
Note:64 is the twice of the wife's age 32.