This is the solution for the Algebra plane geometric figure problem as asked by an anonymous visitor which read, "catrina and tom want to buy a rug for a room that s 14 by 15 feet. They want to leave an even strip of flooring uncovered around the edges of the room. How wide a strip if they buy a rug with an area of 110 square feet?"

It's easier to picture this. Draw a rectangle that's almost a square 14 x 15 feet. Within in draw another such figure but smaller. The space between that figure and the 14 x 15 figure is x. Now the smaller square has an area of 110 square feet. We now have an equation :

(15 -x ) (14 -x ) = 110

210 + x^2 -14x - 15x = 110

x^2 - 29x + 210 = 110

x^2 -29x + 100 = 0

(x - 25)(x - 4) = 0

x = 4 or 25 however using 25 would result in negative dimensions which does not make sense. So 4 is the answer

Check: (15 - 4) (14 - 4) = 110 = 11*10 = 110

## Sunday, December 4, 2011

### Plane Geometric Figure Problem 3 Solution

## Saturday, December 3, 2011

### Number Problem 14 Solution

This is the solution for the Algebra number word problem which was asked by an anonymous visitor that read, "55 bowls of the same size capacity of food.

1. everyone gets their own bowl of soup

2. every two gets one bowl of spaghetti to share

3. every three will get one bowl of salad

4. all r required to have their own helping of salad, spaghetti, and soup."

Ok you know the total number of people is x. Since '" every two gets one bowl of spaghetti to share" then x/2 of the people will have those bowls and since "every three will get one bowl of salad" then x/3 of the people will have those bowls in which they will total 55 bowls.

So we have:

x + x/2 + x/3 = 55 ** multiply by 6

6x + 3x + 2x = 330

11x = 330

x = 30

So there are 30 bowls for soup, 30/2 = 15 bowls for spaghetti , and 30/3 = 10 bowls for salad.

Check 30 + 15 + 10 = 55

### Finance Problem 4 Solution

This is the solution to the Algebra finance word problem a anonymous user asked, "An administrative assistant orders cellular phones for people in her department. The brand A phones cost $89.95 and the brand b phones $34.95.If she ordered 3 times as many brand b phones as brand a phones at a total cost of $584.40, how many of each did she order?"

Ok to make things easier lets make it cents. Just remember to divide by 100 when done to get the answer in dollars and cents...

So brand A is 8995 and b is 3495 which had 3 times as many sold as a and all the combinations of phones totalled 58440.

So 8995x + 3495(3x) = 58440

8995x + 10485x = 58440

19480x = 58440

x = 3 So there were 3 brand A's and 3(3) = 9 brand B's sold.

### Finance Problem 3 Solution

This is the solution to the Algebra finance word problem asked by an anonymous user which read, "Alex has made 42 of the 48 payments he owes on his car but is having trouble continuing to make the payment in full. He has made an arrangement with the bank to pay 2/3rds of his monthly payment, rather than the entire payment, every month. How many months will it take Alex to pay off his car loan with this new payment arrangement?"

Ok, 1st find the remaining months : 48 - 42 = 6 So there are 6 months at full payments. But, you are no longer doing full payments you are doing 2/3s of a payment. So 2/3 of what would equal out 6 ? Or

2x/3 = 6

2x = 18

x = 18/2 = 9 .. So it will take Alex 9 months to pay off his car loan with the new payment arrangement..