Friday, March 13, 2009

Time and Distance Problem 8 Solution

This is the solution to the algebra time and distance word problem # 8:

Distances in this problem are equal, and rate multiplied by time is equal to distance. You have what the times are--- 4 and 5 hours and and the rates are ( x + 15 ) for with the wind of 15 miles per an hour and ( x - 15) for against the wind at 15 miles per an hour.

So we have...

4( x + 15 ) = 5( x - 15 )

4x + 60 = 5x - 75

x = 135 --> This is how fast the vehicle is moving. But with the wind its 135 + 15 or 150 miles an hour going and 135 - 15 or 120 miles an hour coming back.

To check this 4(150) = 5(120) 600 = 600 ---> You also now know the distance was 600 miles, which was not asked in the problem.





1 comment:

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