This is the solution to the algebra age problem # 4... "A man is 27 years older than his son and 10 years from now, he will be twice as old as his son. how old is each now?"

Let x = the son and x + 27 = the man(father)

in 10 years the son will be x + 10 and the father x + 27 + 10 or x + 37 years old. So if he will be twice as old as his son then "twice" the sons age then will "equal" each other.

So, 2(x+10) = x + 37

multiply by 2 on the left side

2x + 20 = x + 37

x = 17 This makes sense since 10 + 17 = 27 and 17 + 37 = 54 which is twice the sons age 10 years from now. So the son is 17 and the father is 17 + 27 or 44 years old.

## Sunday, August 2, 2009

### Age Problem 4 Solution

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nice...,

ReplyDeletenice problem...!

ReplyDeleteglad you liked it! Spread the word -- lol

ReplyDeletei need help on a crazy type of word problem. HELP ME!! im stuck with out an efficient way of solving it.

ReplyDeleteJim can fill a pool carrying buckets of water in 30 minutes. Sue can do the same job in 45 minutes. Tony can do the same job in 1 ½ hours. How quickly can all three fill the pool together?

Ok I submitted the problem and answer on here go to the main page

ReplyDeletePol is 10 years younger than greg. In 7 years, he will be 10 years more than one halfas old as greg. Find their age at present. help me solve it.

ReplyDeleteOk I will help you but for future reference would you mind posting this on the problem side under where you post questions. Thanks. I will post this as a new problem on the problem side here soon.

ReplyDeletei solved it before i looked at the solution.

ReplyDeletemy answer for the kid is 9 and 36 for the father.

in present time their age is

F = S + 27

and for the future

F + 10 = 2S + 10

using matrix or determinance u will get

the age of 9 for his son and 36 for his father.

REMEMBER THE NOTE THAT THE ''he(the father) will be twice as old as his son.

TO CHECK.

9 x 2 = 18

36/2 = 18

^^, hope i helped you confuse your mind lol XDD

The answer in work problem is 15mins.

ReplyDeletePol is 10 years younger than greg. In 7 years, he will be 10 years more than one halfas old as greg. Find their age at present. help me solve it.\]

ReplyDeletethis the answer and the solution.

P=G-10

P+7=1/2G+10

It will become P=G-10 and P-1/2G=3

substitute the P and it will become

G-10-1/2G=3 (You should make the fraction into decimal and it will become 0.5G)

G-10-0.5G=3 transpose the same variable

since we will minus 0.5 from 1 it will become 0.5 so it will become 0.5G=13 now you should make the 0.5 to 1 because we can't divide it so we should times the both side to 0.2 so it will become G=26 <<<<< this is for Greg and we should get the age of Pol. Just substitute it to the equation

so P=16 and G=26

sorry for my wrong grammars because Im a Pilipino and I'm only 8th grader hope you understand my ans.

for table method.

ReplyDeletepresent future

man 27+x 27+x+10

Son x 2(x+10)

27+x+10 = 2(x+10)

37+x = 2x+20

37-20 = 2x-x

x= 17

therefore the present age of son now is 17. then the present age of a father is 27+17=44

i have this computations:

ReplyDeletePresent:

Man=27+son's age --->27+x

Son=x;

In 10 yrs:

Man=2(x+27+10)

son=x+10

27+x+10=2(x+10)(twice the son's age in 10 yrs)

37+x=2x+20

-x=-17

x=17; age of the Son

SOn= 17 yo now

if the Present age of the Man is 27+Son

therefore:

Man=27+17

Man=44

K.

ReplyDeleter told s, i was 10 years older than you are now, when you were born. My present age is 50 yrs . Find s's present age ??

ReplyDelete